javascript - Execution order of multiple setTimeout() functions with same interval -

-

consider following javascript code:

function(){     settimeout(function() {         $("#output").append(" 1 ");     }, 1000);     settimeout(function() {         $("#output").append(" 2 ");     }, 1000); }

you can see example on jsfiddle.

can sure value of #output "one two", in order? usually, handle problem this:

function(){     settimeout(function() {         $("#output").append(" 1 ");         $("#output").append(" 2 ");     }, 1000)); }

but can not way because messages server tells me function execute (in example append "one" or append "two"), have execute small delay.

i tested code in internet explorer 9, firefox 14, chrome 20 , opera 12, , output "one two", can sure case?

the spec here.

my interpretation of settimeout step 8 in section 7.3 execution order is supposed guaranteed.

however, investigated issue because when window minimized , maximised in chrome, finding timeouts set in events coming external sources (like websockets or webworkers) being executed in wrong order. assume browser bug , fixed soon.


Comments

Post a Comment

Popular posts from this blog

c# - SelectList with Dictionary, add values to the Dictionary after it's assigned to SelectList -

-
i have following code - dictionary<string, string> mydict = new dictionary<string, string>(); mydict.add("keya", "valuea"); mydict.add("keyb", "valueb"); ienumerable<selectlistitem> myselectlist = new selectlist(mydict, "key", "value") further down in program, want add values mydict . possible? if yes, how? want - myselectlist.mydict.add("keyc", "valuec"); if you're wanting add items mydict, possible, , changes reflected in of myselectlist 's enumerations long changes made before enumeration (e.g. using .tolist() ) generated. as worked example: dictionary<string, string> mydict = new dictionary<string, string>(); mydict.add("keya", "valuea"); mydict.add("keyb", "valueb"); ienumerable<selectlistitem> myselectlist = new selectlist(mydict, "key", "value...
Read more

mysqli - Php Mysqli_fetch_assoc Error : "Warning: Illegal string offset 'name' in" -

-
this question has answer here: php mysqli returns 1 row 3 answers warning: illegal string offset 'name' in c:\xampp\htdocs\connection\index.php on line 31 1", please can me. <?php include('config.php'); $conn = mysqli_connect(db_host, db_user, db_pass, db_name); $sql = "select * users"; $result = mysqli_query($conn, $sql); $rows = mysqli_fetch_assoc($result); ?> and in body tag <?php foreach ($rows $row) { echo $row['name']; }?> you should use mysqli_fetch_all() here rows within $rows @ once. $sql = "select * users"; $result = mysqli_query($conn, $sql) or die(mysqli_error($conn); $rows = mysqli_fetch_all($result); echo "<pre>"; print_r($rows); // check result
Read more

c - "error: subscripted value is neither array nor pointer nor vector", but why? -

-
i writing tic-tac-toe program , writing function player's turn. passing in tic-tac-toe board (a 3x3 array) in form of pointer, b . problem on last line error in title. subscripted value neither array nor pointer nor vector: b[playercoordsx][playercoordsy] = "x"; just testing i've tried multiple different = values. both characters , numerical values not fix issue. here abbreviated code (what hope) relevant bits: void playerturn(int *b); ... int main(void) { int board[2][2]; int (*b)[2][2]; b = &board; ... void playerturn(int *b); ... return 0; } void playerturn(int *b) { int playercoordsx, playercoordsy; while ((playercoordsx != 1 || playercoordsx != 2 || playercoordsx != 3) && (playercoordsy != 1 || playercoordsy != 2 || playercoordsy != 3)) { printf("enter x coordinate use:"); scanf("%i", &playercoordsx); playercoordsx = playercoordsx - 1; pri...
Read more