image - Creating a link between IOS Apps -

-

china has messaging app, app call wechat 微信 300 millions users. wechat, can link other e-commerce app , e-commerce app can send pictures wechat?

how linking app work? far know, ios not support that.

url schemes may help..

here apple document

here tutorial


Comments

Post a Comment

Popular posts from this blog

c# - SelectList with Dictionary, add values to the Dictionary after it's assigned to SelectList -

-
i have following code - dictionary<string, string> mydict = new dictionary<string, string>(); mydict.add("keya", "valuea"); mydict.add("keyb", "valueb"); ienumerable<selectlistitem> myselectlist = new selectlist(mydict, "key", "value") further down in program, want add values mydict . possible? if yes, how? want - myselectlist.mydict.add("keyc", "valuec"); if you're wanting add items mydict, possible, , changes reflected in of myselectlist 's enumerations long changes made before enumeration (e.g. using .tolist() ) generated. as worked example: dictionary<string, string> mydict = new dictionary<string, string>(); mydict.add("keya", "valuea"); mydict.add("keyb", "valueb"); ienumerable<selectlistitem> myselectlist = new selectlist(mydict, "key", "value...
Read more

mysqli - Php Mysqli_fetch_assoc Error : "Warning: Illegal string offset 'name' in" -

-
this question has answer here: php mysqli returns 1 row 3 answers warning: illegal string offset 'name' in c:\xampp\htdocs\connection\index.php on line 31 1", please can me. <?php include('config.php'); $conn = mysqli_connect(db_host, db_user, db_pass, db_name); $sql = "select * users"; $result = mysqli_query($conn, $sql); $rows = mysqli_fetch_assoc($result); ?> and in body tag <?php foreach ($rows $row) { echo $row['name']; }?> you should use mysqli_fetch_all() here rows within $rows @ once. $sql = "select * users"; $result = mysqli_query($conn, $sql) or die(mysqli_error($conn); $rows = mysqli_fetch_all($result); echo "<pre>"; print_r($rows); // check result
Read more

c - "error: subscripted value is neither array nor pointer nor vector", but why? -

-
i writing tic-tac-toe program , writing function player's turn. passing in tic-tac-toe board (a 3x3 array) in form of pointer, b . problem on last line error in title. subscripted value neither array nor pointer nor vector: b[playercoordsx][playercoordsy] = "x"; just testing i've tried multiple different = values. both characters , numerical values not fix issue. here abbreviated code (what hope) relevant bits: void playerturn(int *b); ... int main(void) { int board[2][2]; int (*b)[2][2]; b = &board; ... void playerturn(int *b); ... return 0; } void playerturn(int *b) { int playercoordsx, playercoordsy; while ((playercoordsx != 1 || playercoordsx != 2 || playercoordsx != 3) && (playercoordsy != 1 || playercoordsy != 2 || playercoordsy != 3)) { printf("enter x coordinate use:"); scanf("%i", &playercoordsx); playercoordsx = playercoordsx - 1; pri...
Read more