javascript - Capture words not followed by symbol -

i need capture (english) words except abbreviations pattern are:

"_any-word-symbols-including-dash."

(so there underscore in beginning , dot in end letters , dash in middle)

i tried smthing this:

/\b([a-za-z-^]+)\b[^\.]/g

but seems don't understand how work negative matches.

update:

i need not match wrap words in tags:

"a words _abbr-abrr. here" should get:

<w>a</w> <w>some</w> <w>words</w> _abbr-abbr. <w>a</w> <w>here</w>

so need use replace correct regex:

test.replace(/correct regex/, '<w>$1</w>')

so can use:

/\b([^_\s]\w*(?!\.))\b/g

unfortunately, there no lookbehind in javascript, can't similar trick "not prefixed _".

example:

> = "a words _abbr. here" > a.replace(/\b([^_\s]\w*(?!\.))\b/g, "<w>$1</w>") "<w>a</w> <w>some</w> <w>words</w> _abbr. <w>a</w> <w>here</w>"

following comment -. updated regex is:

/\b([^_\s\-][\w\-]*(?!\.))\b/g  > "abc _abc-abc. abc".replace(/\b([^_\s\-][\w\-]*(?!\.))\b/g, "<w>$1</w>") "<w>abc</w> _abc-abc. <w>abc</w>"

EXIT