class - Are these java classes equivalent? -
given following 2 classes example1 , example2 , excluding performance characteristics, these 2 classes operate exact same way. is, regardless of how simple or complex either methoda or methodb or can be, result of running these 2 classes, under possible conditions (both internal , external), absolutely same?
example1
public class example1 { public static void main (string [] args) { try { // not compile since nextboolean() not static // boolean t = java.util.random.nextboolean(); // changed java.util.random r = new java.util.random(); boolean t = r.nextboolean(); if (t) { methoda(); methodb(); } } catch (throwable t) { t.printstacktrace(system.out); } } private static void methodb () { // code goes here } private static void methoda () { // code goes here } } example2
public class example2 { public static void main (string [] args) { try { boolean t = java.util.random.nextboolean(); if (t) { methoda(); } if (t) { methodb(); } } catch (throwable t) { t.printstacktrace(system.out); } } private static void methodb () { // code goes here } private static void methoda () { // code goes here } }
the results not guaranteed absolutely same, although in general be. specifically, can write methoda , methodb implementation yield different results when run in example1 , example2, if class names of main program made same before execution.
one way accomplish generate stack trace , introspect on line number execution of methodb, different in example1 , example2.
for example, below methodb result in different output when run in example1 , example2.
public static void methodb() { int count = 0; stacktraceelement[] elements = thread.currentthread().getstacktrace(); (stacktraceelement element : elements) { count += element.getlinenumber(); } system.out.println(count); } however, in general programs yield same results since type of logic based on stack traces or other such aspects unusual.
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